The calculation of the main technical and economic indicators cable line – Abstract

Federal
Agency communication


State
educational institution


Higher
professional education


“Siberian
State University


Telecommunications
and Informatics”


(GOUVPO
“SibSUTI”)

Department


PMM


Job
No. 1


“Calculation
the main technical and economic
indicators cable line”


at
discipline


“Organization
production at the enterprises of telecommunication”


Fulfilled:

Checked:
Boleskine A. V.


Novosibirsk,
2009


Chapter
No. 1. The total number of ows between the termination
points cable line.


Pope=(L/Lоуп)-1,


where L is
the length of the cable line
km;


Lоуп-
the length of the amplifying section between the PMO
for K-60П, km;


Pope=900/120-1=
7 PCs



Chapter No. 2. The total number of SFC for each
the area between the PMO and across the highway.


The total number
SFC at each site between the PMO:


Pnup*=(L/Lнуп)-1,


where
L is the length
the amplifying section between the PMO;


Lнуп-
the length of the amplifying section between the SFC.


Pnup*=(120/19)-1
≈ 5 PC.


Total
the quantity of SFC numbers across the highway:


Pnup
= Pnup*
∙ (TCS+1),


Pnup
=5 ∙ 6=30 pieces



Chapter 3. The capital cost of
the construction of the cable line.


K=K
* N
∙ L,


where k is
specific capital costs 1 Kan km,
R;


N-
the number of frequency channels,


L
–the length of the cable line
km .


K=
72 ∙ 213 ∙ 900=13802400 R.



Chapter No. 4. The number of employees for
maintenance cable
highway.



  1. Production
    lab.



The number
the staff of production laboratory
is set at the rate of 1 staff
unit for every 200 km of motorway symmetric
the cable line.


CPR.l.=(L/200)
∙ cotp,


where
L
–the length of the cable line
km;



cotp-coefficient
holidays(1,08).


CPR.l.=(900/200)of 1.08=4,86
PCs ed



  1. Group
    on energy and electrodilaysis
    devices on cable and radio relay
    lines.



The number
the state of the group is determined from the calculation:


on
one SUS-0,5 staff units;


on
one OUP of 0.2 units.


H=(0,5
∙ 2+ 0,2 ∙ 7)1,08=2, 59 PCs ed



  1. Repair and restoration
    brigade.



In
team includes:


Senior
electrician 1 PC. units;


The cable guy-jointer
– 4 PCs units.


H=
(1+4)of 1.08 = 5,4 PCs ed



  1. Group
    technical documentation.



In
the team consists of:


Senior
electrician – 1 PC. units;


Electrician(on
every 500 km of cable lines) – 1 PC. units.


H=(1+900/500)of 1.08=3,02 PCs units.



  1. Cable
    plot.



The number
state of the cable section is defined
based on the brand of cable (ISS 7*4) at 1 km
cable standard is 4.2 man-hours in
a month. In the state of the cable phase is over
state defined by the regulations,
set the position of senior
technology and senior electrician.


H=((H∙
L/FMEs)
+ 2∙ Puig)
∙ cotp


where
H-standard
, man-hours per month;



FMEs -monthly Fund of working
time (of 166.6), h;



Puig
the number of sections on the highway.


H=
((4,2 ∙ 900/120) + 2∙ 6) ∙ 1,08= 46,98 PCs ed



  1. Amplifier
    points on the cable routes.



State
service supply amplifier
items included:


Senior
engineer-1 EA. u;


Senior
electrician-1 PC. u;


Electrician
-4 PCs u;


Electrician
service electric feeding
units-1 PC. units.


H=(1+1+4+1)
∙ 1,08=7,56 PCs ed


Common
the number:


H=4,86+2,59+5,4+3,02+37,46+7,56=60,89≈61чел



Chapter No. 5. To calculate the cost
the operation of the cable line.


Costs:


1. OPF=H
∙ ZSR ∙ k
∙ 12,


where H-
the total number of people;


ZSR-
average salary, R;


k-district
ratio(1,2).


OPF=61
∙ 4500 ∙ 1,2 ∙ 12=3952800 R


2.
ESN=0,262 * PH,


ESN=0,262
∙ 3952800=1034633,6 R


3.
A=(OPF(capital costs) ∙ PA)/100,


A=(13802400
∙ 6,7)/100=924760,8 R


Of the total
cost contributions BPA, ECH, And are 49,56
%.


Find
total cost:


Zobs=((BPA+UST+A)
∙ 100)/49,56,


Zobs=(3952800+1034633,6
+924760,8) ∙ 100/49,56=11929367,23 R


4. Z
El.EN=SOS ∙ 0,013,


SEL.EN.=
11929367,23 ∙ 0,013=155081,77 R


5. ZM=Sobs
∙ 0,07,


ZM=11929367,23
∙ 0,07=835055,7 R


6. DSD=
Sobs ∙ 0,1,


DSD=11929367,23
∙ 0,1=1192936,7 R.



Chapter No. 6. Cost of operation
1 km and 1 Kan-km cable line.


The cost
operation of 1 km of cable trunk:


C=Sobs/L;


C=11929367,23
/900=13254,85 R.


The cost
operation 1кан-km cable line:


C=SOS/(L

N),


where N is
the number of frequency channels.


C=11929367,23
/(900*213)=62,23 R.


Chapter
No. 7. Drawing the cable line in
scale indicating the ows and the SFC.


Contents:



Chapter
No. 1. The total number of ows between the termination
points cable line. 2


Chapter
No. 2. The total number of SFC for each
the area between the PMO and across the highway. 2


Chapter
No. 3. Capital costs for the construction
the cable line. 2


Chapter
No. 4. The number of employees for
maintenance cable
highway. 2


Chapter
No. 5. To calculate the cost of operation
the cable line. 4


Chapter
No. 6. The cost of operation of 1 km and
1 Kan-km cable line. 5


Chapter
No. 7. Drawing the cable line in
scale indicating the ows and the SFC. 6


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